solve this f(x)=10+5x-xsqure
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f(x)=10+5x-x²
-x² +5x +10 =0
x² -5x -10 =0
on comparing this eq with standard form of quadratic equation ax²+bx+c =0
a= 1 ,b = -5 and c= -10
Discriminant D = b²-4ac
D= -5² - 4×1×-10=> D = 25+40 = 65
x= -b+-√D /2a = 5+- √65 /2 = 5+- 8.06 /2
when positive
x= 5 +8.06/2
= 13.06/2
= 6.53
when negative
x= 5-8.06 /2 = -3.06/2 = 1.53
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