solve this:-f(x)dx+g(y)dy=0
hukam0685:
what has to be calculate
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An exact equation is in the form
f(x) dx + g(y) dy = 0
and, has the property that
dx f = dy g
(If the differential equation does not have this property then we can't proceed any further).
As a result of this, if we have an exact equation then there exists a function h(x, y) such that
Dy h = f and Dx h = g
So then the solutions are in the form
h(x, y) = c
by using the fact of the total differential. We can find then h(x, y) by integration and thus prove:
f(x)dx+g(y)dy=0
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