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k x - y = 2
6 x - 2 y = 3
a1 = k
a2 = 6
b1 = - 1
b2 = - 2
c1= 2
c2 = 3
For unique solution
a1/a2 = c1/c2
= k/6 = 2/3
= k = 2/3 × 6 = 4
k is 4
For no solutions :
k ≠ 4
For infinite solutions :
a1/a2 = b1/b2 = c1/c2
Hence the equation does not have infinite solutions for any value of k.
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