Question

Solve this I will mark u as brilliant​

Answer 1

Answer:

$(\frac{9}{8} ) {}^{ - 3} \times (\frac{9}{8} ) {}^{2} = \frac{1}{( \frac{9}{8}) {}^{3} } \times (\frac{9}{8} ) {}^{2} \\ \\ = > (\frac{8}{9} ) {}^{3} \times (\frac{9}{8} ) {}^{2} = \frac{8}{9}$

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