Question

Solve this identities question​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Θ(theta) = 0

Step-by-step explanation:

let Θ(theta) = 0

$(\frac{1+sin(theta)-cos(theta)}{1+sin(theta)+cos(theta)} )^{2}=\frac{1-cos(theta)}{1+cos(theta)}$

$(\frac{1+sin(0)-cos(0)}{1+sin(0)+cos(theta)} )^{2}=\frac{1-cos(0)}{1+cos(0)}$

$(\frac{1+0-1}{1+0+1} )^{2}=\frac{1-1}{1+1}$

$(\frac{0}{2} )^{2}=\frac{0}{2}$

$0^{2}=0$

$0=0$

RHS = LHS

hence Θ(theta) = 0

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