Question

solve this mate yaar ​

Answer 1

Answer:

$= \frac{tan\theta(sec\theta+1) + tan\theta(sec\theta-1)}{sec^{2}\theta - 1 } \\\\= \frac{tan\theta sec\theta + tan\theta sec\theta}{sec^{2}\theta - 1 } \\\\= \frac{2tan\theta sec\theta}{{tan}^2\theta} \\\\= \frac{2sec\theta}{tan\theta} \\\\= 2 cosec\theta$

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Answer 2

Step-by-step explanation:

your answer is in the picture

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