Question

Solve this :')
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nhi to fail ho jaunga yr -_- ​

Answer 1

Answer:

Position is given as   x=a+b2  =8.5+2.5t2

 

Position at t=2s,  x2  =8.5+2.5(2)square =18.5 m

Position at t=4 s,   x1  =8.5+2.5(4)square  =48.5 m

Displacement  S=x2−x1  =48.5−18.5=30 m

Time is taken  t=4−2=2 s

Average velocity  = S upon t = 30 upon 2 = 15 m/s.  

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is this question most important for you jo tum fail ho jaoge

Answer 2

Answer:

at t = 0s and 2s the velocity is 5.0 m/s^2.

the average velocity is also 5.0 m/s^2.

Explanation:

given: a = 8.5 m b = 2.5 (m/s^2)

alpha is the position along x-axis which is equal to a + bt^2

t is in seconds

velocity (v) = d/dt (displacement)

displacement (s) = d/dt (position)

v = d/dt ( d/dt (position) )

= d/dt ( d/dt (a + bt^2) )

= d/dt ( 0 + 2bt )

= 2b which is constant at all time.

v = 2b is independent of time.

= 2×2.5 = 5.0 m/s^2.