Math, asked by amisha64, 1 year ago

Solve this one.....

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Answered by Anonymous
1

 =  \frac{4 \sqrt{3}  - 5 \sqrt{2} }{ \sqrt{48} -  \sqrt{18}  }  \\  =  \frac{4 \sqrt{3} - 5 \sqrt{2}  }{ \sqrt{48} -  \sqrt{18}  }  \times  \frac{ \sqrt{48}  +  \sqrt{18} }{ \sqrt{48}  +  \sqrt{18} }  \\  =  \frac{4 \sqrt{3} - 5 \sqrt{2}( \sqrt{48}  +  \sqrt{18}  ) }{ ({ \sqrt{48} })^{2} - ( { \sqrt{18} })^{2} }  \\  =  \frac{ 4 \sqrt{3}  - 5 \sqrt{2} (4 \sqrt{3}  + 3 \sqrt{2})}{30} \\  =  \frac{48 + 12 \sqrt{6} - 20 \sqrt{6} - 30  }{30}   \\  =  \frac{18 - 8 \sqrt{6} }{30} \\  =  \frac{2(9 - 4 \sqrt{6} )}{30}  \\  =  \frac{9 - 4 \sqrt{6} }{15}

Anonymous: What's the answer?
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