Solve this plz and tell me answer
Answers
Problem number 4:
Total value of purchased solar panel = Rs.85,000
Rate of GST = 5%
ITC = 5% of 85,000
= 5/100 * 85,000
= Rs.4,250
Total value of selling solar panel = Rs.90,000
Output tax = 5/100 * 90,00
= Rs.4,500
GST payable = Output tax - ITC
= 4500 - 4250
= Rs.250
Therefore,
The amount GST payable is Rs.4500 but which Malhotra payable is Rs.250.
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Problem number 5.1:
Let the son's present age be x and the father's present age be y.
Let the father's new age be [y+(y-x)].
Let the son's new age be [x + (y-x)].
Therefore,
The some of those = 126.(new age)
y + (y-x) + (x + (y-x)) = 126
2y - x + y = 126
∴ 3y - x = 126
Previous age..
[y - (y-x)] + [x - (y-x)] = 38
x + x - y + x = 38
3x - y = 38
∴ y = 3x - 38
Now sub equ(2) into equation 1
3(3x-38) - x = 126
9x - 114 - x = 126
8x = 240
∴ x = 30
Now y = 3x - 38
y = 3(30) - 38
∴ y = 52
The son is 30 years old, and the father is 52 years old.
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Problem number 5.2:
Let the divisor of 6123 be x.
Quotient is x.
Remainder = 1/2 of x.
= x/2
As per the formula,
Dividend = Divisor * Quotient + remainder
6123 = x * x +x/2
x² + x/2 - 6123 = 0
2x² + x - 12246 = 0
2x² + 157x - 156x - 12246 = 0
x ( 2x + 157) - 78 (2x+157) = 0
(2x + 157) (x-78) = 0
2x + 157 = 0 x = 78
2x = -157
x = - 157/2
Therefore, divisor is 78 or - 157/2.
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Problem number 6.1:
Given,
P[A] = 2P[B]
P[B] = 2P[C]
P[A] = 2[2P[C]]
= 4P[C]
As given in the question,
P[A] + P[B] + P[C] = 1
4P[C] + 2P[C] + P[C] = 1
P[C] = 1/7
P[A] = 4P[C] = 4/7
P[B] = 2P[C] = 2/7
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Problem number 6.2:
As given..
a18 = 52
a + 17d = 52 --- (1)
a39 = 148
a+ 38d = 148 -- (2)
Adding 1 and 2..
a + 17d + a + 38d = 52 + 148
2a + 55d = 200 ....(3)
Sn = n/2[2a + (n – 1)d]
S56 = 56/2[2a + (56 – 1) d]
S56 = 28 [2a + 55d]
S56 = 28 [200] (from eq.3)
S56 = 5600
Sum of first 56 terms of A.P. is 5600.
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