Math, asked by rohit807, 1 year ago

solve this problem fast

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Answered by NishantMishra3
2
heyy mate !!

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solution:


 \frac{sin   \theta}{1 - cos \theta}  \times \frac{1 + cos \theta}{1  + cos \theta} \\   \\  =  >  \frac{sin \theta + sin \theta.cos \theta}{ 1 -  {cos}^{2} \theta }  \\  \\  =  >  \frac{sin \theta(1 +cos \theta) }{1 - (1 -  {sin}^{2} \theta) }  \\  \\  =  >  \frac{1 + cos \theta}{sin \theta}



hope it helps u❤❤❤
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