Question

Solve this problem now...​

Answer 1

Answer:

In ΔPOQ, we have

DE∥OQ(Given)

By Basic proportionality Theorem, we have

EQ

PE

=

DO

PD

…(i)

Similarly,

In ΔPOR, we have

DF∥OR(Given)

∴

DO

PD

=

FR

PF

…(ii)

Now, from (i) and (ii), we have

EQ

PE

=

FR

PF

⇒EF∥QR

[Applying the converse of Basic proportionality Theorem in ΔPQR]

Thank you ♡

Answer 2

Explanation:

Answer is in the attachment with complete steps.