solve this problem very urgent
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good question bro
LHS=
sinA - cosA+1/sinA +cosA-1
=> we multipley cosA OK
=> cosA(sinA-cosA+1)/cosA(sinA+cosA-1)
=> cosA(sinA-cosA+1)/sinAcosA+cos²A-cosA
=> cosA(sinA-cosA+1)/1-sin²A-cosA+sinAcosA
=> cosA(sinA-cosA+1)/(1-sinA) (1+sinA)-cosA(1-sinA)
=> cosA(sinA-cosA+1)/(1-sinA) (1+sinA-cosA)
=>cosA/1-sinA
Divided by cosA and fond it
cosA
____
cosA
__________
1 sinA
___ _ ____
cosA cosA
=> 1/secA-tanA
heans prove
LHS=RHS.
_____swarnim__#####
LHS=
sinA - cosA+1/sinA +cosA-1
=> we multipley cosA OK
=> cosA(sinA-cosA+1)/cosA(sinA+cosA-1)
=> cosA(sinA-cosA+1)/sinAcosA+cos²A-cosA
=> cosA(sinA-cosA+1)/1-sin²A-cosA+sinAcosA
=> cosA(sinA-cosA+1)/(1-sinA) (1+sinA)-cosA(1-sinA)
=> cosA(sinA-cosA+1)/(1-sinA) (1+sinA-cosA)
=>cosA/1-sinA
Divided by cosA and fond it
cosA
____
cosA
__________
1 sinA
___ _ ____
cosA cosA
=> 1/secA-tanA
heans prove
LHS=RHS.
_____swarnim__#####
Anonymous:
hay this is helpful
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thanks
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