Math, asked by 7976338231, 1 year ago

solve this question 20 ,21

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Answered by chiragmendiratp76b4j
0

tera paper a raha ha or tu abhi bhi ncert kar raha ha bhai kuc or kar le kuc bann jayga


chiragmendiratp76b4j: sorry i didn't give your answer
Answered by niral
1

Answer:

Step-by-step explanation:

(20) ans=area of rectangle is 63x5 or 315 cm^2

Let the two parallel sides by 16x and 5x.

area of trap = (average of 2 parallel sides)(height)

= ((16x + 5x)/2)(5) = (4/15)(315)

105x/2 = 84

105x = 168

x = 8/5 = 1.6

The two sides are 25.6 and 8

check:

area = (25.6+8)/2(5) = 84

and (4/15)(315) = 84

(21) ans= area of rectangular field=4356m^2

length of field = 99m

breadth = area/length=4356/99=44m

width of the road=4.5m

area of the road parallel to the length=99*4.5=445.5m^2

area of the road parallel to the breadth=44*4.5=198m^2

and area of the common square portion=4.5*4.5=20.25m^2

total area of the road= 445.5+198-20.25=623.25sq.m

area of each square stone=1.5*1.5 sq.m

required number of stone for road =623.25/1.5*1.5 =277

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