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The answer is given below
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paras39:
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then
2^x = Z
3^x = Y
72^x = (3^2 × 2^3)^x
=> 3^2x × 2^3x
=> Y^2 × z^ 3
2^x = Z ( cube both side to get 2^3x = z^3)
3^x = Y ( square both side to get 3^2x = Y^2 )
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