Question

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Answer 1

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Answer 2

To prove:- AB+CD=AD+BC
Proof:- Since, the length of tangents drawn from an external point to a circle are equal.
AP=AS
BP=BQ
RD=SD
CR=CQ
Adding all of the above
(AP+BP)+(DR+CR) = (AS+DS)+(BQ+CQ)
→ AB+CD = BC+AD
Hence, proved.