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Solution
Given :-
- [4^(n+1).2^n - 8^n]/ [2^(3m)] = 3/8
To Prove :-
- n + 1 = m
Explanation
Given by question,
➡ [4^(n+1).2^n - 8^n]/ [2^(3m)] = 3/8
➡ [ 2^(2n+2) . 2^n - 2^(3n)]/[2^(3m)} = 3/2^3
➡[ 2^(3n+2) - 2^(3n)]/[2^(3m)] = 3/2^3
➡2^(3n)[(2^2) - 1]/2^(3m) = 3/2^3
➡ 2^(3n-3m) = (3/2^3) × (1/3)
➡ 2^(3n-3m) = 1/2^3
Or,
➡ 2^(3n-3m) = (1/2)^3
Or,
➡2^(3n-3m) = 2^(-3)
We know,
If, a^m = a^n , then,
- m = n,
So,
➡ 3n - 3m = -3
➡ 3n + 3 = 3m
➡3(n+1) = 3m
Or,
➡ n + 1 = m
That's proved.
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