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royo:
thanks you sir
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distance=√(x2-x1)^2+(y2-y1)^2
(x1,y1)=(2,3)
(x2,y2)=(4,1)
distance between them=√(4-2)^2+(1-3)^2
=√2^2+(-2)^2
=√4+4
=√16
=4
therefore, distance between(2,3) and(4,1)=4(ans)
hope it will help you. if you are satisfied with my answer then mark my answer as brainlist answer please
(x1,y1)=(2,3)
(x2,y2)=(4,1)
distance between them=√(4-2)^2+(1-3)^2
=√2^2+(-2)^2
=√4+4
=√16
=4
therefore, distance between(2,3) and(4,1)=4(ans)
hope it will help you. if you are satisfied with my answer then mark my answer as brainlist answer please
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