solve this t²-15 by middle term splitting
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=t²-0t-15
=(t-√5 ) (t+√5)
The value of t²-15 is Zero when t-√15 =0 or t+√15 =0 when,t=√15 or t=-√15
Therefore,the zeroes of t²-15 are √15 and -√15
→Sum of zeroes =√15-(√15)=0 =-0/1=-(coefficient of t )/(coefficient of t²)
→Product of zeroes =(√15)(-√15)=-15 -15/1 =constant term /coefficient of x²
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Answered by
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Explanation:
(t-√5)(t+√5)
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