Question

solve this!!!
$\sqrt[2]{(\frac{x}{y}){xy} } = 5$
then find the value of x .

Answer 1

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Hey

Here is your answer,

√(x/y)xy = 5

√(x)(x) = 5

√x^2 = 5

X = 5

Hope it helps you!

Answer 2

your question is -----> $\sqrt[2]{\left(\frac{x}{y}\right){xy}}=5$

as you know, $\frac{a}{\cancel{b}}\times\cancel{b}=a$

so, here we can do
$\frac{x}{\cancel{y}}\times x\cancel{y}=x^2$

so, $\sqrt{\left(\frac{x}{y}\right)\times{xy}}=\sqrt{x^2}=x$

so, $\sqrt[2]{\left(\frac{x}{y}\right){xy}}=x=5$

hence, value of x = 5