Question

solve (x+2) square=2(x+3)​

Answer 1

${(x + 2)}^{2} = 2(x + 3)$

$\implies \: {x}^{2} + 4 + 4x = 2x + 6 \\ \\ \implies \: {x}^{2} + 4 + 4x - 2x - 6 = 0 \\ \\ \implies \: {x}^{2} + 2x - 2 = 0$

here , a = 1 , b = 2 , C = -2

D = b² - 4ac

D = 2² - 4(1)(-2)

D = 4 + 8

D = 12

so,

the roots would be

$\frac{-b±√D}{2a}$

$\frac{-2+√12}{2}$, $\frac{-2-√12}{2}$