Question

solve x-3(2+x)>2(3x-1),x€{-3,-2,-1,0,1,2} set builder form

Answer 1

Answer:

Solving the inequality we get

x < -0.5

=> x = -2 or -3

Answer 2

hey mate

here is the solution....

x-3(2+x)>2(3x-1) where x € {-3, ...2}

=>x-6-3x>6x-2

=>-2x-6>6x-2

=>-8x>4

=>x<4/-8

(reversing the sign of inequality as dividing both sides by -ve no)

=>x<-½

thus,

solution set :x={-3,-2,-1}

thus,

set builder form:{x:x€-z, -3<=X<=-1}