solve
x2−2000x+21879
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Answer:
X^2+2000X-21879=0
a = 1; b = 2000; c = -21879;
Δ = b2-4ac
Δ = 20002-4·1·(-21879)
Δ = 4087516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
X1=−b−Δ√2aX2=−b+Δ√2a
The end solution:
Δ−−√=4087516−−−−−−−√=4∗1021879−−−−−−−−−√=4√∗1021879−−−−−−−√=21021879−−−−−−−√
X1=−b−Δ√2a=−(2000)−21021879√2∗1=−2000−21021879√2
X2=−b+Δ√2a=−(2000)+21021879√2∗1=−2000+21021879√2
Step-by-step explanation:
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