solve
x²+2x+3 plz telll the answer
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Answered by
0
Here is your answer :-
x² + 2x +3 =0
a = 1 , b = 2 , c = 3
D = b² -4ac
= 4 - 12 = -8
x = -b±√D/2a
= -2±√-8/2
= -2±2√2i/2. ( √-1 = i )
= -1±√2i
x = -1+√2i or -1-√2i
If u like my answer then pls mark as brainiliest
x² + 2x +3 =0
a = 1 , b = 2 , c = 3
D = b² -4ac
= 4 - 12 = -8
x = -b±√D/2a
= -2±√-8/2
= -2±2√2i/2. ( √-1 = i )
= -1±√2i
x = -1+√2i or -1-√2i
If u like my answer then pls mark as brainiliest
Answered by
1
x^2 + 2x + 3 = 0
x^2+ 3x- x +3 = 0
x (x+3) -1 (x+3) = 0
(x+3) (x-1) = 0
x+3 = 0
x = -3
x+1 = 0
x = -1
x^2+ 3x- x +3 = 0
x (x+3) -1 (x+3) = 0
(x+3) (x-1) = 0
x+3 = 0
x = -3
x+1 = 0
x = -1
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