Math, asked by manavigoel, 11 months ago

solve x2 +5√5x-70 =0

Answers

Answered by Selaphiel
33

Answer:

Step-by-step explanation:

Attachments:
Answered by Anonymous
4

Given:

x2 +5√5x-70 =0

To find:

The solution of x2 +5√5x-70 =0

Solution:

On solving x2 +5√5x-70 =0, x= -7\sqrt{5} and x=2\sqrt{5}.

We can find the solution by following the given steps-

We know that the equation is quadratic and has 2 roots.

The equation: x2 +5√5x-70 =0

On factorizing it, we get

x^{2}+7\sqrt{5}x-2\sqrt{5}x-70=0

x(x+7\sqrt{5})-2\sqrt{5}(x+7\sqrt{5})=0

(x+7\sqrt{5})(x-2\sqrt{5})=0

To get the values of x, we will equate both the terms in brackets to 0.

(x+7\sqrt{5})=0

(x-2\sqrt{5})=0

So, the solutions of the equation are as follows-

x= -7\sqrt{5} and x=2\sqrt{5}

Therefore, on solving x2 +5√5x-70 =0, x= -7\sqrt{5} and x=2\sqrt{5}.

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