Solve. y-7/ 1-(2y+1)= 2/3. Class 8
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Let us work on LHS and RHS separately.
LHS= y-7/ 1- (2y + 1).
Now LHS= y-7 ÷ [ 1- 2y - 1 ]
= y-7 ÷ (-2y)
This is equal to RHS = 2/3.
Therefore, y-7÷ (-2y) = 2/3
⇒ y- 7 = -4y/3
⇒ y + 4y/3 = 7
⇒ 7y/3 = 7
⇒ y/3= 1
⇒ y= 3
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