Question

solve: y²-x² dy/dx = x×y dy/dx​

Answer 1

Step-by-step explanation:

y2+x2(dydx)=xy(dydx)y2+x2(dydx)=xy(dydx)

yx+xy(dydx)=(dydx)yx+xy(dydx)=(dydx)

yx+(xy−1)(dydx)=0yx+(xy−1)(dydx)=0

Let yx=uyx=u

y=xuy=xu

dydx=xdudx+udydx=xdudx+u

Substituting dydxdydx and yxyx

u+(1u−1)(x

Answer 2

Answer:

dy/dx y²-x²

=2y-2x

=2(y-x)

Step-by-step explanation:

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