Question

some body quickly help me ?????

Answer 1

okkk so now I will try to explain

L.H.S

[4+3√-20]½ + [4-3√-20]½,

[4+3×2√5i]½ + [4-3×2√5i]½,

now we can write it as,

[{3²+(√5i)²+2×3×√5i}²]½ + [{3²+(√5i)²-2×3×√5i}²],

[{3+√5i}²]½ + [{3-√5i}²]½,

then it will becomes

(3+√5i)+(3-√5i),

3+√5i+3-√5i,

6,

hence

L.H.S=R.H.S