Question

some imli seeds. she made groups of five with them. found one seed was left over. she tried making groups of Six and groups four one seeds was left over. what is the smallest no. of seed sthat sunita had

Answer 1

The answer will be found by finding the HcF of 5, 6 and 4 which is 60.
Since always one seed is left so no. Of seeds is 60 plus 1 equals to 61.

Answer 2

Given:

Groups of four, five, and six is being created by Sunita in which in every time one seed remains intact.

So, from the given information we can now calculate the LCM of 4, 5, 6 and add 1 to the LCM.

LCM of 4, 5, and 6 is 60

Adding 1 to the LCM we get, 61

Therefore:

The smallest number of seeds that Sunita had is 61.