someone please give me tricks to solve triangles of class 10
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there as no tricks but u should have to read the example of the chapter then u solve the problem easily . wish this help u .
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The ratio of a with angle angle 30°,60°,& 90° is 1:√3:2
The ratio of with angle 45°,45°,90 is 1:1:√2
In a circle of radius r, the length of a chord of central angle c° is (c/2)°
The ratio of with angle 45°,45°,90 is 1:1:√2
In a circle of radius r, the length of a chord of central angle c° is (c/2)°
jrc:
asked how to solve the sums in exams (the tricks)
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