Someone please help me understanding differentiation..in question 14
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y α t²
y = kt² (let k be a constant)
(1.)
For initial velocity i.e. at t=0
Velocity = dy/dt = 2kt
At t=0
Velocity = 2k(0) = 0
Therefore velocity is zero.
(2)
As the velocity is the function t, so it is variable.
now,
acceleration = f = d²y/dt² = 2k = constant
Therefore, it is uniform ( constant) acceleration.
y = kt² (let k be a constant)
(1.)
For initial velocity i.e. at t=0
Velocity = dy/dt = 2kt
At t=0
Velocity = 2k(0) = 0
Therefore velocity is zero.
(2)
As the velocity is the function t, so it is variable.
now,
acceleration = f = d²y/dt² = 2k = constant
Therefore, it is uniform ( constant) acceleration.
Shivam901:
thanks
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