Somewhere in the wonder land there are sequence of 7 temples separated by 7 rivers, sequence is temple, river, temple, river………… a man has to put equal number of flowers on every temple but the catch is as he crossed the river, remaining flowers will be doubled (2 times) how many flowers should a man carry with him before entering into first temple so that till last river he has left with nothing?
Answers
Answered by
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He should carry multiples of 127 and leave multiples of 64.
Step-by-step explanation:
Let's assume he took 5 flowers,.
On first temple he dropped 2 flowers. Now remaining are = 5 - 3 = 3 flowers. Remaining is 3 as he crossed the river it will become 6. He put same number of flowers (i.e 2 flowers) 6 - 2 = 4 which again become twice in second river means 8…
Solution:
He should carry multiples of 127 and leave multiples of 64.
Smallest option is 127 to carry and 64 to leave
Answered by
0
Answer:
127 flowers
And left 64 flowers at each temple
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