Question

specific conductivity of a 0.12 normal solution of an electrolyte is 0.024 per ohm per centimetre determine its equivalent conductivity​

Answer 1

Answer:

πeq = 1000K/N

K = .024SiemanCm^-1

N = . 12

πeq = 24/0.12

πeq = 200siemanCm^2eq^-1

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