Question

spliting the middle term of 3x^2-6x+4​

Answer 1

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❤.Answer:-

=3x^2-7x+4

=3x^2-3x-4x+4

=3x(x-1)+4(x-1)

=x=1=-4/3

Answer 2

Step-by-step explanation:

3x2-6x+4=0

(3x2-6x) +4 = 0

3x2-6x+4=0

divide both sides of the equation 3 has to have 1 as the coefficient of the first term

x2-2x-(4/3)= 0

Add 4/3 on both sides of the equation

x2-2x=4/3

one has completed left hand side into a perfect square

4/3+1or (4/3)+(3/3)

give us 7/3

so adding two both sides we finally get

x2-2x+1=7/3