Square of 2x²– 3y² please tell ans fast
Answers
Mathematics Solutions Solutions for Class 8 Math Chapter 6 Algebraic Expressions are provided here with simple step-by-step explanations. These solutions for Algebraic Expressions are extremely popular among Class 8 students for Math Algebraic Expressions Solutions come handy for qui
Answer:
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Step-by-step explanation:
Equation of the curve is 2x2 + 3y2 = 5
Differentiating w.r.t. x, we get
4x + 6y
dy
dx
⋅dydx = 0
∴
dy
dx
4x
6y
dydx=-4x6y
∴ Slope of the tangent at (1, 1) is
dy
dx
(dydx)(1,1) =
-4(1)6(1)=-23
∴ Equation of tangent at (a, b) is
y - b =
dy
dx
a, b(dydx)(a, b) (x - a)
Here, (a, b) ≡ (1, 1)
∴ Equation of the tangent at (1, 1) is
(y - 1) =
-23(x - 1)
∴ 3(y - 1) = - 2(x - 1)
∴ 3y - 3 = - 2x + 2
∴ 3y - 3 = - 2x + 2
∴ 2x + 3y - 5 = 0
Slope of the normal at (1, 1) is
dy
dx
-1(dydx)(1,1)
=32
∴ Equation of normal at (a, b) is
y - b =
dy
dx
ab
-1(dydx)(a,b) (x - a)
∴ Equation of the normal at (1, 1) is
(y - 1) =
32(x - 1)
∴ 2y - 2 = 3x - 3
∴ 3x - 2y - 1 = 0
Concept: Introduction of Derivatives
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