Math, asked by mahemunnisha, 5 hours ago

square root of product of 4th and 6th term of GP is 7. find the series​

Answers

Answered by rraghu3056
1

Answer:

question is incomplete question is that what you doing now

Answered by MasterKaatyaayana2
0

Answer:

a, a^{3/4}\sqrt[4]{7} ,\sqrt{7a} ,  7^{3/4}\sqrt[4]{a}, 7, ..............

Step-by-step explanation:

Nth term of the GP is given by

T_n = ar^{n-1}\\

Given that,

\sqrt{T_4T_6} =7\\\implies ar^4 = 7\\\implies r =\sqrt[4]{ \frac{7}{a} }

so general GP gfor any arbitary constant a is given by

a, a^{3/4}\sqrt[4]{7} ,\sqrt{7a} ,  7^{3/4}\sqrt[4]{a}, 7, ..............

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