Question

Starting from a stationary position, anil paddles his bicycle to attain a velocity of 10 m/s in 25s. then he applies brakes such that he again comes to rest after next 50s. calculate the accelaration of the bicycle in both cases. also find the total distance covered by anil

Answer 1

Answer:

Acceleration for first case = 0.4 m/s²

Acceleration for first case = -0.2

Distance for first case = 1.25 m

Distance for first case = 25 m

Explanation:

Velocity= 10m/s

Time1 = 25 s

Time2 = 50 s

Initial velocity = u = 0 m/s

Final velocity = v = 10 m/s

Acceleration = ?

Acceleration = (v-u)/t

(10-0)/25

10/25

2/5 = 0.4 m/s² = Acceleration

Now taking out the distance,

Here distance = displacement = s (s is the sign of displacement)

Applying 2 law of equation of motion

2as = v² - u²

2(0.4)s = 10² - 0²

0.8s = 100

s = 100/0.8

s = 1.25 m

Now seeing the second case,

Given,

Initial velocity = u = 10 m/s

Final velocity = v = 0 m/s

Time = 50s

Acceleration = ?

Acceleration = (v-u)/t

(0-10)/50

-10/50

-1/5 = -0.2 = Acceleration

Now taking out the distance,

Here distance = displacement = s (s is the sign of displacement)

Applying 2 law of equation of motion

2as = v² - u²

2(-0.2)s = 0² - 10²

-0.4s = -100

s = -100/-0.4

s = 25 m

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