Question

Starting from a stationary position Rahul paddles his bicycle to attain a velocity of 6ms in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4ms in the next 5s. Calculate the acceleration of the bicycle in both cases​

Answer 1

Answer:

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Explanation:

Now in the first case, Rahul paddles from the starting point so his initial velocity is zero and attains a velocity of 6 m/s in 30 sec. ... ⇒a=630=0.2ms−2. So in the first case his acceleration is 0.2ms−2 . Now in the second case he applies brakes such that the velocity of the bicycle comes down to 4m/s in the next 5s.

Answer 2

Answer:

0.2 m/s² & 0.4m/s²

Explanation:

Case 1

u=0m/s

v=6m/s

t=30s

By Newton's laws of motion,

v=u+at

a=(v-u)/t

=(6-0)/30

= 0.2 m/s²

Case 2

Here the initial velocity is 6m/s

final velocity is 4m/s

t=5s

a=(v-u)/t

=(4-6)/5

= - 0.4 m/s²