starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6m/s in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4m/s in the next 5s. Calculate the acceleration of the bicycle in both the cases.
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For first case:
Initial velocity =0
Final velocity =60m/s
Time =30sec
v=u+at
6=0+a×30
6=30a
a= 30/6=0.2
a=0.2m/s^2
For second case:
Initial velocity =6m/s
Final velocity =4m/s
Time taken =5sec
v=u+at
4=6+a×5
4−6=5a
−2=5a
a=− 2/5
a=−0.4m/s^2
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Explanation:
For first case:
Initial velocity =0
Final velocity =60m/s
Time =30sec
v=u+at
6=0+a×30
6=30a
a= 30
. 6
=0.2
a=0.2m/s
2
For second case:
Initial velocity =6m/s
Final velocity =4m/s
Time taken =5sec
v=u+at
4=6+a×5
4−6=5a
−2=5a
a=− 5
. 2
a=−0.4m/s
2
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