Question

Starting from rest, what will be Mahendra's velocity after 1 second if he is falling down due to gravitational force of earth ?

Answer 1

the answer of this question is see in photo

Answer 2

Dear Student,

● Answer -

v = 9.8 m/s

◆ Explanation -

# Given -

t = 1 s

g = 9.8 m/s^2

# Solution -

Let v be Mahendra's velocity after 1 second.

Applying Newtons 1st law of motion,

v = u + gt

v = 0 + 9.8×1

v = 9.8 m/s

Hence, Mahendra's velocity after 1 second from free fall is 9.8 m/s.

Thanks dear. Hope this helps you..