State and prove expression for electric feild due to two charged thin sheet
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12th
Physics
Electric Charges and Fields
Applications of Gauss Law
State Gauss law in electros...
PHYSICS
State Gauss law in electrostatics. Using the law derive an expression for electric field due to a uniformly charged thin spherical shell at a point outside the shell.
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Gauss Law:
Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.
Electric field due to a uniformly charged thin shell:
In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q.
Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.
ϕ=E.Scosθ
So, ϕ=E.4πr
2
−−−−−−−−−−−−−−(1)
As per gauss law,
ϕ=
ϵ
o
q
−−−−−−−−−(2)
From equation (1) and (2)
E.4πr
2
=
ϵ
o
q
Now,
E=
4πϵ
o
r
2
q
This is the electric field at the distance r, outside from the shell.
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