state of hybridization of Xe in cationic part of solid in XeF6
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Type of hybridisation/steric no. = (no. of sigma bonds + no. of lone pairs)
it should be sp3d3spX3X223dX3, however according to my textbook it is sp3d2spX3X223dX2 in solid state. That is how it was written(in my textbook), emphasising on the fact that "in solid state it is sp3d2spX3X223dX2". How does solid state of a compound changes its hybridisation
it should be sp3d3spX3X223dX3, however according to my textbook it is sp3d2spX3X223dX2 in solid state. That is how it was written(in my textbook), emphasising on the fact that "in solid state it is sp3d2spX3X223dX2". How does solid state of a compound changes its hybridisation
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ratherrather than writing I had root how to solve and the explanation is also given in the figure hope this might be prove helpful to you if it is so and if answer is correct then please give it star rating and thanks to its also please do not forget to follow me back and help me to become brainliest
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