Question

What is mass of h2o in 1000kg cuso4.5h20

Answer 1

molecular mass of CuSO4 . 5H2O=249.5gm=249.5 X 10^-3Kg

249.5 X 10^-3 Kg of cuso4.5h2o contains 90X10^-3Kg water

then,1000Kg will contain (90 X 10^-3 / 249.5 X 10^-3) X 1000

ie = 36.08Kg of H2O

Answer 2

Answer: The mass of $H_2O$ present will be 360.721 kg

Explanation:

We are given a compound of copper sulfate penta hydrate.

The molecular mass of this compound will be =

$[63.5+32+(4\times 16)+(5\times 18)]=249.5g/mol$

In 1 mole of copper sulfate, 90 grams of water is present.

Or,

In 249.5 grams, the amount of water present is 90 grams.

Or,

In 0.2495 kg of copper sulfate, the amount of water present is 0.090 kg.     (Conversion factor: 1 kg = 1000 g)

So, in 1000 grams of copper sulfate, the amount of water present will be = $\frac{0.090}{0.2495}\times 1000=360.721kg$

Hence, the mass of $H_2O$ present will be 360.721 kg