Question

state that whether X + root 2 is a factor of x cube minus x square - 2 + root 2 X + root 2​

Answer 1

Answer:

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Answer 2

Answer:

Applying remainder theorem, we get

x+1=0

x=−1

Now,

x

3

−x

2

−(2+

2

)x+

2

Replacing x with −1, we get

=(−1)

3

−(−1)

2

−(2+

2

)(−1)+

2

=−1−1+2+

2

+

2

=2

2

Hence, (x+1) is not a factor of polynomial x

3

−x

2

−(2+

2

)x+

2

.