Question

state the coefficient of x square in 7 x cube minus 5 x square + 13 x square - 28​

Answer 1

Step-by-step explanation:

The given polynomial can be written as:

(2x−5)(2x

2

−3x+1)=4x

3

−6x

2

+2x−10x

2

+15x−5

=4x

3

−16x

2

+17x−5

So, the coefficient of x

2

in the given polynomial is −16.

Answer 2

Question:

State the coefficient of x² in 7x³ - 5x² + 13x² - 28

Answer:

8

Step-by-step explanation:

→ 7x³ - 5x² + 13x² - 28

Take -x² common from -5x² + 13x² and solve it

→ 7x³ -x²(5 - 13) - 28

→ 7x³ -x²(-8) - 28

Now,

(+)(-) = (-)

(-)(+) = (-)

(+)(+) = (+)

(-)(-) = (+)

So,

→ 7x³ + 8x² - 28

Hence, the coefficient of x² in 7x³ - 5x² + 13x² - 28 is 8.