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Step-by-step explanation:
Let us assume that 3√2/4 is rational. Hence it can be written in the form of p/q (q is not equal to zero) where p and q are co-primes.
3√2/4=p/q
Squaring both sides
9×2/16=p²/q²
9/8=p²/q²
9q²=8p²
Now, p² is divisible by q², this means p² is also divisible by q.
Let p=3x
=> 9q²=8(3x)²
9q²=8(9x²)
q²=8x²
Since, q² is divisible by x², this means q² is also divisible by x.
Let q=4y
=> (4y)²=8x²
16y²=8x²
2y²=x²
This means that p and q have some common factor.
This contradicts the fact that a and b are co-primes.
This contradiction has arisen due to our incorrect assumption of 3√2/4 as rational.
Hence, 3√2/4 is irrational.
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