Question

stone is thrown upwards from a tower with a velocity 50 . Another stone is simultaneously thrown downwards from the same location with a velocity 50 . When the first stone is at the highest point, the relative velocity of the second stone with respect to the first stone is (assume that second stone has not yet reached the ground)

Answer 1

Answer:

Explanation:

h=u^2/2g

h=2500/20 = 125 m

125 = 50t-5t^2

5t^2-50t+125=0

t^2-10t+25=0

t=5 sec

v=u+at

v=50 m/s

relative velocity  = v1-v2 = v1 = 50 m/s downwards