Chemistry, asked by anvikam, 9 months ago

Subjective
lonisation potential and electron affinity of fluorine are 17.42 and 3.45eV
respectively. Calculate the electronegativity of fluorine.

Answers

Answered by haripriya200365

2

Explanation:

according to mullikan equation,

electronegativity=ionisation potential+electron

affinity/5.6

electronegativity of fluorine=17.42+3.45/5.6

=3.726

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