Question

subract a^3+3a^2b-b^3 from the sum of 2a^3-b^3 and 4ba^2-a^3+b^3-1​

Answer 1

Step-by-step explanation:

(3a - 2b + 4c) + (3b - 2c) - (a - b - c)

= 3a - 2b + 4c + 3b - 2c - a + b + c

= 2a + 2b + 3c

Answer 2

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction, Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Hope it helps ❤️

Hi ^_^

I am Divi