Question

Subtract(2x-3y+4z) from the sum of (x+3y-4z),(4z-y+9z) and (-2x+3y-z).

Answer 1

(X + 3y - 4z) + (4z - y + 9z) +( - 2x+3y-z)
- x + 5y + 8z

(-x + 5y + 8z) - ( 2x - 3y +4z)
-3x + 8y +4z

Answer 2

Answer:

$-3x+8y+4z$

Step-by-step explanation:

First find the sum of (x+3y-4z),(4z-y+9z) and (-2x+3y-z).

So, $x+3y-4z+4z-y+9z-2x+3y-z$

$-x+5y+8z$

Now we are given that Subtract(2x-3y+4z) from the sum of (x+3y-4z),(4z-y+9z) and (-2x+3y-z).

So, $-x+5y+8z-(2x-3y+4z)$

$-x+5y+8z-2x+3y-4z$

$-3x+8y+4z$

Hence the answer is $-3x+8y+4z$