Subtract 4x²+9xy-9xy-9y² from 6x²=3xy+4y²
Answers
Answer:
Chapter 7: Algebraic Expressions Exercise – 7.2
Question: 1
Add the following:
(i) 3x and 7x
(ii) -5xy and 9xy
Solution:
We have
(i) 3x + 7x = (3 + 7) x = 10x
(ii) -5xy + 9xy = (-5 + 9)xy = 4xy
Question: 2
Simplify each of the following:
(i) 7x3y +9yx3
(ii) 12a2b + 3ba2
Solution:
Simplifying the given expressions, we have
(i) 7x3y + 9yx3 = (7 + 9)x3y = 16x3y
(ii) 12a2b + 3ba2 = (12 + 3)a2b =15a2b
Question: 3
Add the following:
(i) 7abc, -5abc, 9abc, -8abc
(ii) 2x2y, - 4x2y, 6x2y, -5x2y
Solution:
Adding the given terms, we have
(i) 7abc + (-5abc) + (9abc) + (-8abc)
= 7abc – 5abc + 9abc – 8abc
= (7 – 5 + 9 – 8)abc
= (16 – 13)abc
= 3abc
(ii) 2x2y +(-4x2y) + (6x2y) + (-5x2y)
= 2x2y - 4x2y + 6x2y - 5x2y
= (2- 4 + 6 - 5) x 2y
= (8 - 9) x 2y
= -x2y
Question: 4
Add the following expressions:
(i) x3 -2x2y + 3xy2- y3, 2x3- 5xy2 + 3x2y - 4y3
(ii) a4 - 2a3b + 3ab3 + 4a2b2 + 3b4, - 2a4 - 5ab3 + 7a3b - 6a2b2 + b4
Solution:
Adding the given expressions, we have
(i) x3 -2x2y + 3xy2- y3, 2x3- 5xy2 + 3x2y - 4y3
Collecting positive and negative like terms together, we get
x3 +2x3 - 2x2y + 3x2y + 3xy2 - 5xy2 - y3- 4y3
= 3x3 + x2y - 2xy2 - 5y3
(ii) a4 - 2a3b + 3ab3 + 4a2b2 + 3b4, - 2a4 - 5ab3 + 7a3b - 6a2b2 + b4
a4 - 2a3b + 3ab3 + 4a2b2 + 3b4 - 2a4 - 5ab3 + 7a3b - 6a2b2 + b4
Collecting positive and negative like terms together, we get
a4 - 2a4- 2a3b + 7a3b + 3ab3 - 5ab3 + 4a2b2 - 6a2b2 + 3b4 + b4
= - a4 + 5a3b - 2ab3 - 2a2b2 + 4b4
Question: 5
Add the following expressions:
(i) 8a – 6ab + 5b, –6a – ab – 8b and –4a + 2ab + 3b
(ii) 5x3 + 7 + 6x - 5x2, 2x2 – 8 - 9x, 4x - 2x2 + 3 x 3, 3 x 3 - 9x - x2 and x - x2 - x3 - 4
Solution:
(i) Required expression = (8a – 6ab + 5b) + (–6a – ab – 8b) + (–4a + 2ab + 3b)
Collecting positive and negative like terms together, we get
8a – 6a – 4a – 6ab – ab + 2ab + 5b – 8b + 3b
= 8a – 10a – 7ab + 2ab + 8b – 8b
= –2a – 5ab
(ii) Required expression = (5 x 3 + 7+ 6x - 5x2) + (2 x 2 – 8 - 9x) + (4x - 2x2 + 3 x 3) + (3 x 3 - 9x-x2) + (x - x2 - x3 - 4)
Collecting positive and negative like terms together, we get
5x3 + 3x3 + 3x3 - x3 - 5x2 + 2x2 - 2x2- x2 - x2 + 6x - 9x + 4x - 9x + x + 7 – 8 - 4
= 10x3 - 7x2 - 7x - 5
Question: 6
Add the following:
(i) x – 3y – 2z
5x + 7y – 8z
3x – 2y + 5z
(ii) 4ab – 5bc + 7ca
–3ab + 2bc – 3ca
5ab – 3bc + 4ca
Solution:
(i) Required expression = (x – 3y – 2z) + (5x + 7y – 8z) + (3x – 2y + 5z)
Collecting positive and negative like terms together, we get
x + 5x + 3x – 3y + 7y – 2y – 2z – 8z + 5z
= 9x – 5y + 7y – 10z + 5z
= 9x + 2y – 5z
(ii) Required expression = (4ab – 5bc + 7ca) + (–3ab + 2bc – 3ca) + (5ab – 3bc + 4ca)
Collecting positive and negative like terms together, we get
4ab – 3ab + 5ab – 5bc + 2bc – 3bc + 7ca – 3ca + 4ca
= 9ab – 3ab – 8bc + 2bc + 11ca – 3ca
= 6ab – 6bc + 8ca
Question: 7
Add 2x2 - 3x + 1 to the sum of 3x2 - 2x and 3x + 7.
Solution:
Sum of 3x2 - 2x and 3x + 7
= (3x2 - 2x) + (3x +7)
=3x2 - 2x + 3x + 7
= (3x2 + x + 7)
Now, required expression = 2x2 - 3x + 1+ (3x2 + x + 7)
= 2x2 + 3x2 - 3x + x + 1 + 7
= 5x2 - 2x + 8
Question: 8
Add x2 + 2xy + y2 to the sum of x2 - 3y2and 2x2 - y2 + 9.
Solution:
Question: 9
Add a3+ b3 - 3 to the sum of 2a3 - 3b3 - 3ab + 7 and -a3 + b3 + 3ab - 9.
Solution:
Question: 10
Subtract:
(i) 7a2b from 3a2b
(ii) 4xy from -3xy
Solution:
(i) Required expression = 3a2b -7a2b
= (3 -7)a2b
= - 4a2b
(ii) Required expression = –3xy – 4xy
= –7xy
Question: 11
Subtract:
(i) - 4x from 3y
(ii) - 2x from – 5y
Solution:
(i) Required expression = (3y) – (–4x)
= 3y + 4x
(ii) Required expression = (-5y) – (–2x)
= –5y + 2x
Question: 12
Subtract:
(i) 6x3 −7x2 + 5x − 3 from 4 − 5x + 6x2 − 8x3
(ii) − x2 −3z from 5x2 – y + z + 7
(iii) x3 + 2x2y + 6xy2 − y3 from y3−3xy2−4x2y
Solution:
Question: 13
From
(i) p3 – 4 + 3p2, take away 5p2 − 3p3 + p − 6
(ii) 7 + x − x2, take away 9 + x + 3x2 + 7x3
(iii) 1− 5y2, take away y3 + 7y2 + y + 1
(iv) x3 − 5x2 + 3x + 1, take away 6x2 − 4x3 + 5 + 3x
Solution:
Question: 14
From the sum of 3x2 − 5x + 2 and − 5x2 − 8x + 9 subtract 4x2 − 7x + 9.
Solution:
Question: 15
Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7.
Solution:
Sum of (13x – 4y + 7z) and (–6z + 6x + 3y)
= (13x – 4y + 7z) + (–6z + 6x + 3y)
= (13x – 4y + 7z – 6z + 6x + 3y)
= (13x + 6x – 4y + 3y + 7z – 6z)
= (19x – y + z)
Sum of (6x – 4y – 4z) and (2x + 4y – 7)
= (6x – 4y – 4z) + (2x + 4y – 7)
= (6x – 4y – 4z + 2x + 4y – 7)
= (6x + 2x – 4z – 7)
= (8x – 4z – 7)
Now, required expression = (8x – 4z – 7) – (19x – y + z)
= 8x – 4z – 7 – 19x + y – z
= 8x – 19x + y – 4z – z – 7
= –11x + y – 5z – 7
Question: 16
From the sum of x2 + 3y2 − 6xy, 2x2 − y2 + 8xy, y2 + 8 and x2 − 3xy subtract −3x2 + 4y2 – xy + x – y + 3.
Solution:
Question: 17
What should be added to xy – 3yz + 4zx to get 4xy – 3zx + 4yz + 7?
Solution:
The required expression can be got by subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7.
Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)
= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx
= 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7
= 3xy – 7zx + 7yz + 7
Step-by-step explanation:
Question: 1
Add the following:
(i) 3x and 7x
(ii) -5xy and 9xy
Solution:
We have
(i) 3x + 7x = (3 + 7) x = 10x
(ii) -5xy + 9xy = (-5 + 9)xy = 4xy
Question: 2
Simplify each of the following:
(i) 7x3y +9yx3
(ii) 12a2b + 3ba2